Integrand size = 29, antiderivative size = 267 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {\left (40 a^4-36 a^2 b^2+3 b^4\right ) x}{8 b^6}-\frac {2 a \left (5 a^4-7 a^2 b^2+2 b^4\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{b^6 \sqrt {a^2-b^2} d}+\frac {a \left (15 a^2-11 b^2\right ) \cos (c+d x)}{3 b^5 d}-\frac {\left (20 a^2-13 b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^4 d}+\frac {\left (5 a^2-3 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{3 a b^3 d}-\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d (a+b \sin (c+d x))} \]
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Time = 0.55 (sec) , antiderivative size = 267, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.241, Rules used = {2971, 3128, 3102, 2814, 2739, 632, 210} \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=-\frac {\left (a^2-b^2\right ) \sin ^3(c+d x) \cos (c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {a \left (15 a^2-11 b^2\right ) \cos (c+d x)}{3 b^5 d}-\frac {\left (20 a^2-13 b^2\right ) \sin (c+d x) \cos (c+d x)}{8 b^4 d}+\frac {\left (5 a^2-3 b^2\right ) \sin ^2(c+d x) \cos (c+d x)}{3 a b^3 d}-\frac {2 a \left (5 a^4-7 a^2 b^2+2 b^4\right ) \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{b^6 d \sqrt {a^2-b^2}}+\frac {x \left (40 a^4-36 a^2 b^2+3 b^4\right )}{8 b^6}-\frac {\sin ^3(c+d x) \cos (c+d x)}{4 b^2 d} \]
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Rule 210
Rule 632
Rule 2739
Rule 2814
Rule 2971
Rule 3102
Rule 3128
Rubi steps \begin{align*} \text {integral}& = -\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\int \frac {\sin ^2(c+d x) \left (15 a^2-8 b^2-a b \sin (c+d x)-4 \left (5 a^2-3 b^2\right ) \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{4 a b^2} \\ & = \frac {\left (5 a^2-3 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{3 a b^3 d}-\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\int \frac {\sin (c+d x) \left (-8 a \left (5 a^2-3 b^2\right )+5 a^2 b \sin (c+d x)+3 a \left (20 a^2-13 b^2\right ) \sin ^2(c+d x)\right )}{a+b \sin (c+d x)} \, dx}{12 a b^3} \\ & = -\frac {\left (20 a^2-13 b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^4 d}+\frac {\left (5 a^2-3 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{3 a b^3 d}-\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\int \frac {3 a^2 \left (20 a^2-13 b^2\right )-a b \left (20 a^2-9 b^2\right ) \sin (c+d x)-8 a^2 \left (15 a^2-11 b^2\right ) \sin ^2(c+d x)}{a+b \sin (c+d x)} \, dx}{24 a b^4} \\ & = \frac {a \left (15 a^2-11 b^2\right ) \cos (c+d x)}{3 b^5 d}-\frac {\left (20 a^2-13 b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^4 d}+\frac {\left (5 a^2-3 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{3 a b^3 d}-\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\int \frac {3 a^2 b \left (20 a^2-13 b^2\right )+3 a \left (40 a^4-36 a^2 b^2+3 b^4\right ) \sin (c+d x)}{a+b \sin (c+d x)} \, dx}{24 a b^5} \\ & = \frac {\left (40 a^4-36 a^2 b^2+3 b^4\right ) x}{8 b^6}+\frac {a \left (15 a^2-11 b^2\right ) \cos (c+d x)}{3 b^5 d}-\frac {\left (20 a^2-13 b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^4 d}+\frac {\left (5 a^2-3 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{3 a b^3 d}-\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d (a+b \sin (c+d x))}-\frac {\left (a \left (5 a^4-7 a^2 b^2+2 b^4\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{b^6} \\ & = \frac {\left (40 a^4-36 a^2 b^2+3 b^4\right ) x}{8 b^6}+\frac {a \left (15 a^2-11 b^2\right ) \cos (c+d x)}{3 b^5 d}-\frac {\left (20 a^2-13 b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^4 d}+\frac {\left (5 a^2-3 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{3 a b^3 d}-\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d (a+b \sin (c+d x))}-\frac {\left (2 a \left (5 a^4-7 a^2 b^2+2 b^4\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{b^6 d} \\ & = \frac {\left (40 a^4-36 a^2 b^2+3 b^4\right ) x}{8 b^6}+\frac {a \left (15 a^2-11 b^2\right ) \cos (c+d x)}{3 b^5 d}-\frac {\left (20 a^2-13 b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^4 d}+\frac {\left (5 a^2-3 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{3 a b^3 d}-\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d (a+b \sin (c+d x))}+\frac {\left (4 a \left (5 a^4-7 a^2 b^2+2 b^4\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{b^6 d} \\ & = \frac {\left (40 a^4-36 a^2 b^2+3 b^4\right ) x}{8 b^6}-\frac {2 a \left (5 a^4-7 a^2 b^2+2 b^4\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{b^6 \sqrt {a^2-b^2} d}+\frac {a \left (15 a^2-11 b^2\right ) \cos (c+d x)}{3 b^5 d}-\frac {\left (20 a^2-13 b^2\right ) \cos (c+d x) \sin (c+d x)}{8 b^4 d}+\frac {\left (5 a^2-3 b^2\right ) \cos (c+d x) \sin ^2(c+d x)}{3 a b^3 d}-\frac {\cos (c+d x) \sin ^3(c+d x)}{4 b^2 d}-\frac {\left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d (a+b \sin (c+d x))} \\ \end{align*}
Time = 2.89 (sec) , antiderivative size = 325, normalized size of antiderivative = 1.22 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {-\frac {384 a \left (5 a^4-7 a^2 b^2+2 b^4\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{\sqrt {a^2-b^2}}+\frac {960 a^5 c-864 a^3 b^2 c+72 a b^4 c+960 a^5 d x-864 a^3 b^2 d x+72 a b^4 d x+24 b \left (40 a^4-31 a^2 b^2+b^4\right ) \cos (c+d x)+\left (40 a^2 b^3-21 b^5\right ) \cos (3 (c+d x))-3 b^5 \cos (5 (c+d x))+960 a^4 b c \sin (c+d x)-864 a^2 b^3 c \sin (c+d x)+72 b^5 c \sin (c+d x)+960 a^4 b d x \sin (c+d x)-864 a^2 b^3 d x \sin (c+d x)+72 b^5 d x \sin (c+d x)+240 a^3 b^2 \sin (2 (c+d x))-176 a b^4 \sin (2 (c+d x))-10 a b^4 \sin (4 (c+d x))}{a+b \sin (c+d x)}}{192 b^6 d} \]
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Time = 1.76 (sec) , antiderivative size = 382, normalized size of antiderivative = 1.43
method | result | size |
derivativedivides | \(\frac {-\frac {2 a \left (\frac {-b^{2} \left (a^{2}-b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-a^{3} b +a \,b^{3}}{\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a}+\frac {\left (5 a^{4}-7 a^{2} b^{2}+2 b^{4}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}}\right )}{b^{6}}+\frac {\frac {2 \left (\left (\frac {3}{2} a^{2} b^{2}-\frac {5}{8} b^{4}\right ) \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (4 a^{3} b -4 a \,b^{3}\right ) \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (\frac {3}{2} a^{2} b^{2}+\frac {3}{8} b^{4}\right ) \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (12 a^{3} b -8 a \,b^{3}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-\frac {3}{2} a^{2} b^{2}-\frac {3}{8} b^{4}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (12 a^{3} b -\frac {20}{3} a \,b^{3}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-\frac {3}{2} a^{2} b^{2}+\frac {5}{8} b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+4 a^{3} b -\frac {8 a \,b^{3}}{3}\right )}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{4}}+\frac {\left (40 a^{4}-36 a^{2} b^{2}+3 b^{4}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4}}{b^{6}}}{d}\) | \(382\) |
default | \(\frac {-\frac {2 a \left (\frac {-b^{2} \left (a^{2}-b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-a^{3} b +a \,b^{3}}{\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a}+\frac {\left (5 a^{4}-7 a^{2} b^{2}+2 b^{4}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}}\right )}{b^{6}}+\frac {\frac {2 \left (\left (\frac {3}{2} a^{2} b^{2}-\frac {5}{8} b^{4}\right ) \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (4 a^{3} b -4 a \,b^{3}\right ) \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (\frac {3}{2} a^{2} b^{2}+\frac {3}{8} b^{4}\right ) \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (12 a^{3} b -8 a \,b^{3}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-\frac {3}{2} a^{2} b^{2}-\frac {3}{8} b^{4}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (12 a^{3} b -\frac {20}{3} a \,b^{3}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\left (-\frac {3}{2} a^{2} b^{2}+\frac {5}{8} b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+4 a^{3} b -\frac {8 a \,b^{3}}{3}\right )}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{4}}+\frac {\left (40 a^{4}-36 a^{2} b^{2}+3 b^{4}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{4}}{b^{6}}}{d}\) | \(382\) |
risch | \(\frac {5 x \,a^{4}}{b^{6}}-\frac {9 x \,a^{2}}{2 b^{4}}+\frac {3 x}{8 b^{2}}-\frac {2 i a^{2} \left (a^{2}-b^{2}\right ) \left (i b +a \,{\mathrm e}^{i \left (d x +c \right )}\right )}{b^{6} d \left (-i b \,{\mathrm e}^{2 i \left (d x +c \right )}+i b +2 a \,{\mathrm e}^{i \left (d x +c \right )}\right )}+\frac {3 i {\mathrm e}^{2 i \left (d x +c \right )} a^{2}}{8 b^{4} d}+\frac {2 a^{3} {\mathrm e}^{i \left (d x +c \right )}}{b^{5} d}-\frac {5 a \,{\mathrm e}^{i \left (d x +c \right )}}{4 b^{3} d}+\frac {2 a^{3} {\mathrm e}^{-i \left (d x +c \right )}}{b^{5} d}-\frac {5 a \,{\mathrm e}^{-i \left (d x +c \right )}}{4 b^{3} d}+\frac {i {\mathrm e}^{-2 i \left (d x +c \right )}}{8 b^{2} d}-\frac {i {\mathrm e}^{2 i \left (d x +c \right )}}{8 b^{2} d}-\frac {3 i {\mathrm e}^{-2 i \left (d x +c \right )} a^{2}}{8 b^{4} d}-\frac {5 \sqrt {-a^{2}+b^{2}}\, a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a +\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,b^{6}}+\frac {2 \sqrt {-a^{2}+b^{2}}\, a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a +\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,b^{4}}+\frac {5 \sqrt {-a^{2}+b^{2}}\, a^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a -\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,b^{6}}-\frac {2 \sqrt {-a^{2}+b^{2}}\, a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i a -\sqrt {-a^{2}+b^{2}}}{b}\right )}{d \,b^{4}}+\frac {\sin \left (4 d x +4 c \right )}{32 b^{2} d}-\frac {a \cos \left (3 d x +3 c \right )}{6 b^{3} d}\) | \(496\) |
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Time = 0.34 (sec) , antiderivative size = 604, normalized size of antiderivative = 2.26 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\left [-\frac {6 \, b^{5} \cos \left (d x + c\right )^{5} - {\left (20 \, a^{2} b^{3} - 3 \, b^{5}\right )} \cos \left (d x + c\right )^{3} - 3 \, {\left (40 \, a^{5} - 36 \, a^{3} b^{2} + 3 \, a b^{4}\right )} d x + 12 \, {\left (5 \, a^{4} - 2 \, a^{2} b^{2} + {\left (5 \, a^{3} b - 2 \, a b^{3}\right )} \sin \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}} \log \left (-\frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2} - 2 \, {\left (a \cos \left (d x + c\right ) \sin \left (d x + c\right ) + b \cos \left (d x + c\right )\right )} \sqrt {-a^{2} + b^{2}}}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}\right ) - 3 \, {\left (40 \, a^{4} b - 36 \, a^{2} b^{3} + 3 \, b^{5}\right )} \cos \left (d x + c\right ) + {\left (10 \, a b^{4} \cos \left (d x + c\right )^{3} - 3 \, {\left (40 \, a^{4} b - 36 \, a^{2} b^{3} + 3 \, b^{5}\right )} d x - 3 \, {\left (20 \, a^{3} b^{2} - 13 \, a b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{24 \, {\left (b^{7} d \sin \left (d x + c\right ) + a b^{6} d\right )}}, -\frac {6 \, b^{5} \cos \left (d x + c\right )^{5} - {\left (20 \, a^{2} b^{3} - 3 \, b^{5}\right )} \cos \left (d x + c\right )^{3} - 3 \, {\left (40 \, a^{5} - 36 \, a^{3} b^{2} + 3 \, a b^{4}\right )} d x - 24 \, {\left (5 \, a^{4} - 2 \, a^{2} b^{2} + {\left (5 \, a^{3} b - 2 \, a b^{3}\right )} \sin \left (d x + c\right )\right )} \sqrt {a^{2} - b^{2}} \arctan \left (-\frac {a \sin \left (d x + c\right ) + b}{\sqrt {a^{2} - b^{2}} \cos \left (d x + c\right )}\right ) - 3 \, {\left (40 \, a^{4} b - 36 \, a^{2} b^{3} + 3 \, b^{5}\right )} \cos \left (d x + c\right ) + {\left (10 \, a b^{4} \cos \left (d x + c\right )^{3} - 3 \, {\left (40 \, a^{4} b - 36 \, a^{2} b^{3} + 3 \, b^{5}\right )} d x - 3 \, {\left (20 \, a^{3} b^{2} - 13 \, a b^{4}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{24 \, {\left (b^{7} d \sin \left (d x + c\right ) + a b^{6} d\right )}}\right ] \]
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Timed out. \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.34 (sec) , antiderivative size = 449, normalized size of antiderivative = 1.68 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\frac {\frac {3 \, {\left (40 \, a^{4} - 36 \, a^{2} b^{2} + 3 \, b^{4}\right )} {\left (d x + c\right )}}{b^{6}} - \frac {48 \, {\left (5 \, a^{5} - 7 \, a^{3} b^{2} + 2 \, a b^{4}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )}}{\sqrt {a^{2} - b^{2}} b^{6}} + \frac {48 \, {\left (a^{3} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - a b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a^{4} - a^{2} b^{2}\right )}}{{\left (a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 2 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a\right )} b^{5}} + \frac {2 \, {\left (36 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 15 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 96 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 96 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 36 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 9 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 288 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 192 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 36 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 9 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 288 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 160 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 36 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 15 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 96 \, a^{3} - 64 \, a b^{2}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{4} b^{5}}}{24 \, d} \]
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Time = 13.04 (sec) , antiderivative size = 1003, normalized size of antiderivative = 3.76 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^2} \, dx=\text {Too large to display} \]
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